Two frames, one stationary and the other moving, are initially coincident. Two observers in the two frames observe a body initially at rest in the coincident frame. A constant force F starts acting on the body along horizontal axis when moving frame starts separation from fixed frame. Work done 'W' as observed by stationary frame and W as observed from moving frame are compared to each other as
W'
W'
Text Solution
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Let u be the speed of moving frame and horizontal distance covered at any instant from moving frame is x then distance from stationary frame is (x + ut)
Work done w.r.t stationary frame W
= F(x + ut)= Fx + Fut
But Fx is the work done w.r.t. moving frame
∴ ∴ W = W' + Fut
i.e., W ≠ ≠ W'
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